Useful tips

Does bromine react with sulphuric acid?

Does bromine react with sulphuric acid?

Bromide ions reduce the sulphuric acid to sulphur dioxide. In the process, the bromide ions are oxidised to bromine. Iodide ions reduce the sulphuric acid to a mixture of products including hydrogen sulphide. The iodide ions are oxidised to iodine.

How does sulphuric acid react with sodium bromide?

Sodium bromide react with sulfuric acid to produce sodium bisulfate, bromine, sulfur dioxide and water. Sodium bromide – solid. Sulfuric acid – heated solution with concentration of over 50%.

What happens when sulphuric acid is added to sodium chloride?

When concentrated Sulphuric acid is added to sodium chloride, sodium bisulphate and hydrochloric acid are formed.

Which halide is the best reducing agent?

iodide ion
Hence , the iodide ion is the most powerful reducing agent among other halides.

What happens when bromide ions are added to sulphuric acid?

The bromide ions reduce the sulphuric acid to sulphur dioxide gas. This is a decrease of oxidation state of the sulphur from +6 in the sulphuric acid to +4 in the sulphur dioxide. You can combine these two half-equations to give the overall ionic equation for the reaction:

What happens when you add chlorine to a bromine pool?

This is because when you add chlorine to a bromine pool it converts the bromide (used up bromine) back into free bromine. When you add bromine to a chlorine pool, on the other hand, the bromine does not go away but builds up over time, creating a chlorine demand. Therefore, when you shock the pool with chlorine,…

How are fluoride and chloride ions related to sulphuric acid?

Fluoride and chloride ions won’t reduce concentrated sulphuric acid. Bromide ions reduce the sulphuric acid to sulphur dioxide. In the process, the bromide ions are oxidised to bromine. Iodide ions reduce the sulphuric acid to a mixture of products including hydrogen sulphide. The iodide ions are oxidised to iodine.

How are ammonium chloride and ammonium bromide prepared?

To prepare the reaction medium, ammonium chloride (4.7482g, 0.04780mol) and ammonium bromide (8.7525g, 0.04780mol) of were mixed with 45ml of ~7.5 M sulfuric acid (H 2 SO 4 ). This mixture was heated to ensure the compounds dissolved fully. Synthesis of t-Butyl Chloride and t-Butyl Bromide from tert-Butyl Alcohol