# What is the surface area of an open box?

## What is the surface area of an open box?

The area of the base of the open box is 5000 cubic inches. The length of each side of the square base is 10 inches. If the height of the box is h, the volume is 10^2*h. The surface area of the open box is 50*10*4 + 100 = 2100 square inches.

## What is the total surface area of Cuboidal box having open top?

The total surface area of cuboidal box having open top is 2h(l + b) + lb….

1. Total surface area of cuboid is 2( lb+ bh + lh) .
2. Lateral surface area is 2h ( l+ b) .
3. Volume of cuboid is l × b × h .
4. Total surface area of cube 6(a)sq.

How do you find the area of a box?

The width, height, and length of a box can all be different. If they are the same, then the box will become a perfectly square box. The volume, or amount of space inside a box is h × W × L. The outside surface area of a box is 2(h × W) + 2(h × L) + 2(W × L)

### What is the surface area of an open top box?

An open-top box with a square base has a surface area of 1200 square inches. How do you find the largest possible volume of the box?

### How to find the surface area of a rectangular box?

The following is the process to find the surface area of rectangular box with its top side missing. Let’s call the side of the square base s and let’s call the height of the prism h. Normally you have 6 sides. However, now you only have 5. You have 4 sides of area h s and one base of area s 2. Therefore, S A = h s + s 2.

How to find the largest possible volume of the box?

An open-top box with a square base has a surface area of 1200 square inches. How do you find the largest possible volume of the box? | Socratic An open-top box with a square base has a surface area of 1200 square inches. How do you find the largest possible volume of the box?

#### What is the area of an open top container?

A manufacturer wishes to compare the cost of producing an open-top cylindrical container and an open-top rectangular container. The area of the base is the area of a circle = π r 2.