# How many gates in a 16-bit ripple carry adder?

## How many gates in a 16-bit ripple carry adder?

9 NAND

A 16-bit ripple-carry adder, implemented using 9 NAND gates, will use 16*9*4=576 transistors.

**How many gate delays ripple carry adder takes to generate 16th carry bit?**

A standard 16-bit ripple-carry adder would take 16 × 3 − 1 = 47 gate delays.

**Why are ripple carry adders slow?**

In a ripple carry adder the sum and carry out bits of any half adder stage is not valid until the carry in of that stage occurs. Propagation delays inside the logic circuitry is the reason behind this. Propagation delay is time elapsed between the application of an input and occurance of the corresponding output.

### How many full adders are required to realize a 16-bit ripple carry adder?

A 16-bit ripple carry adder is realized using 16 identical full adders. The carry propagation delay of each full adder is 12 ns and the sum propagation delay of each full adder is 15 ns.

**What is the gate delay in a 16 bit ripple carry adder?**

For a typical design, the longest delay path through an n-bit ripple carry adder is approximately 2n + 2 gate delays. Thus, for a 16-bit ripple carry adder, the delay is 34 gate delays. This delay tends to be one of the largest in a typical com- puter design.

**What is the drawback of ripple carry adder?**

Ripple-carry adder, illustrating the delay of the carry bit. The disadvantage of the ripple-carry adder is that it can get very slow when one needs to add many bits. To reduce the computation time, there are faster ways to add two binary numbers by using carry look ahead adders.

## What is the disadvantage of ripple carry addition?

Disadvantages of Ripple Carry Adder- Ripple Carry Adder does not allow to use all the full adders simultaneously. Each full adder has to necessarily wait until the carry bit becomes available from its adjacent full adder. This increases the propagation time.

**What is one disadvantage of ripple carry adder?**

**What do you need to know about ripple carry adder?**

To understand the working of a ripple carry adder completely, you need to have a look at the full adder too. Full adder is a logic circuit that adds two input operand bits plus a Carry in bit and outputs a Carry out bit and a sum bit.. The Sum out (Sout) of a full adder is the XOR of input operand bits A, B and the Carry in (Cin) bit.

### Why does a 4 bit adder implement its overflow?

This is because this is 1000 0001 in binary which is also -127 in 2’s complement. If you work through this example, you can see that it is a result of the carry out not equalling the carry in. It is possible to have a correct computation even when the carry flag is high. There is a carry out of 1, but there has been no overflow.

**How to write Verilog code for 16 bit ripple carry adder?**

While writing the verilog code for 16-bit Ripple carry adder the same procedure is used. First the verilog code for 1-bit full adder is written. From this, we can get the 4-bit ripple carry adder. Now,by using this 4-bit ripple carry adder 16-bit ripple carry adder verilog code has been written. Similar way, we can get N-bit ripple carry adder.

**What are the LSB bits for ripple carry adder?**

Here we can see the LSB bits are A0, B0 and C0 where C0 is the input carry bit. Output of 1-bit full adder is S0 and C1. S0=A0⊕B0⊕C0 and C1= (A0⊕B0).C0 + A0B0. A 4-bit Ripple Carry adder is built by cascading four 1-bit full adders in series. The out carry bit of every full adder is fed to the input of the next full adder.